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9r^2-12r-45=0
a = 9; b = -12; c = -45;
Δ = b2-4ac
Δ = -122-4·9·(-45)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-42}{2*9}=\frac{-30}{18} =-1+2/3 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+42}{2*9}=\frac{54}{18} =3 $
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